A small marble is projected with a velocity of 10 m/s in a direction of 45 degree from the horizontal y-direction, along the smooth wadge. Calculate the magnitude v of its velocity after 2 second. Take g=10m/s^2.
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V=√v² + g^2t² - 2vgtsinx
Given v=10m/s
x=45°
t=2sec
Substituting the values
=√100 + (9.8)² x 2² - 2 x 10 x 9.8 x 2 x 1/√2
=√206.93
=14.39m/sec
Given v=10m/s
x=45°
t=2sec
Substituting the values
=√100 + (9.8)² x 2² - 2 x 10 x 9.8 x 2 x 1/√2
=√206.93
=14.39m/sec
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