Question

A small metallic piece weighs 50 g and its volume is
20 cm. It is immersed in water. Calculate the
(a) density of metallic piece, and (b) upthrust on the
metallic piece
​

Answer 1

Step-by-step explanation:

Answer

By Archimedes principle, the weight of liquid displaced is equal to the bouyant force on the object. In this case, the the change in bouyant force is equal to 0.1g.

Also, expression for bouyant force will be,

F=

ρ

s

50

ρ

l

g

In the second case, after expansion,

F

′

=

1+γ

s

ΔT

ρ

s

50

1+γ

l

ΔT

ρ

l

g=F

1+γ

l

ΔT

1+γ

s

ΔT

ΔF=F

′

−F=F

1+γ

l

ΔT

(γ

s

−γ

l

)ΔT

−0.1=45×75

1+75γ

12×10

−6

−γ

γ≈3.1×10

−4

/

0

C

Answer is 3.1×10

−4

/

0

C