A small object is embedded in a glass sphere of refractive index =1.5of radius 5.0cm at a distance 1.5cm left to the centre .Locate the image of the object as seen by an observer standing (a)to the left of the object as seen and (b) to the right of the sphere .
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The image will be formed at 2 cm and 2.65 cm left to corner.
Explanation:
(a) Image seen form left:
u = ( 5 - 15) = - 3.5 cm
R = - 5 cm
μ2 / v - μ1 / u = μ2 - μ1 / R => 1 / v + 1.5 / 3.5 = - 1 - 1.5 / 5
=> 1/v = 1/10 - 3 /7 => v = - 70/23 = - 3 cm (Inside the sphere)
Image will be formed 2 cm left to corner.
(b) Image seen from right:
u = - ( 5 + 1.5) = - 6.5 cm
R = - 5 cm
μ2/v - μ1 / u = μ2 - μ1 / R
1/v + 1.5/6.5 = 1 - 1.5 / -5
=> 1/v = 1/10 - 3 /13
v = - 130 / 17 = - 7.65 cm ( Inside the sphere)
Image will be formed, 2.65 cm left to corner.
Hence the image will be formed at 2 cm and 2.65 cm left to corner.
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