Question

A small object is placed 30cm away from a diverging lens of focal length 10cm. Determine the position and nature of the image

Answer 1

Answer:

v = -7.5

image is virtual and erect.

Explanation:

u = -30

f = -10 ( concave lens)

1/v - 1/u = 1/f

I/v - 1/(-30) = 1/-10

1/v + 1/30 = 1/-10

1/v = 1/-10 - 1/30

= 30+10/-300

= -40/300

= -4/30

v =. -30/4 = -7.5

The image formed by concave lens is 7.5 cm on the same side as that of object.

The image is virtual and erect.

Answer 2

V= -15cm
The image is real and inverted
The position is between F and 2F