A small object is placed at right angles to the axis of a fixed concave mirror so as to form (i) a
real (ii) a virtual image, twice as long as the object. If the radius of curvature of mirror is 40cm,
What is the distance between the two images?
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Given,Focal length, f = 50 cm Magnification, m = 2 m = vu = 2 v = 2u From mirror formula, 1f = 1v + 1u 1f = 12u + 1u u = 3f2 = 3 × 502 = 75 cm ... More
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