Question

A small objects is placed 20cm in front of a block of glass 10cm thick and it's farther side silvered. the image is formed 22cm behind the silvered face. find the refractive index of glass

Answer 1

20+x=22+(10-x)

20+x-10+x=22

10+2x=22

2x=12

X=6

Mu =real thickness ÷apparent thickness=10÷6=1.67

Answer 2

Answer:

The refractive index of glass is 1.67.

Explanation:

Given that,

Object distance = 20 cm

Thickness of glass = 10 cm

Image distance = 22 cm

We need to calculate the refractive index of glass

Using formula for refractive index

$d=2(v+\dfrac{t}{\mu})$

Put the value into the formula

$20+10+22=2(22+\dfrac{10}{\mu})$

$52-40=\dfrac{20}{\mu}$

$\mu=1.67$

Hence, The refractive index of glass is 1.67.