a small particles carrying a negative charge of 1.56*10^-19 is surrounded by equilibrium between the horizontal metal plates 5cm apart having a potential difference of 3000 across them. find the mass of the particles
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Answer:
E = - dv / dr
= -3000 / 5 × 10^-2
mg = qE
m × 9.8 = 1.56 × 10^-19 × ( -3000 / 5 × 10^-2)
m = 9.8 × 10^-16 kg
hope it will help you.....
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