Chemistry, asked by njangandharvan53, 5 months ago

A small piece of wire bent into L shape with upright and horizontal portions of equal length 10cm each. It is
plaed with the horizontal portion along the axis of the concave mirror of focal length 10cm. if the bend is
30cm from the pole. The ratio of the lengths of the images of the upright and horizontal portions of the wire
is
1) 1:2
2) 2:1
3) 1:1
4) 3:1​

Answers

Answered by 8177060393
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Answer:

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Physics

Ray Optics and Optical Instruments

Problems on Mirror and Magnification Formula

A small piece of wire bent ...

PHYSICS

A small piece of wire bent into an L shape, with upright and horizontal portions of equal lengths, is placed with the horizontal portion along the axis of the concave mirror whose radius of curvature is 10 cm. If the bend is 20 cm from the pole of the mirror,then the ratio of the lengths of the images of the upright and horizontal portions of the wire is

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ANSWER

Given, u=−20 ; f=−5

From mirror formula,

v

1

+

u

1

=

f

1

v

1

20

1

=

5

−1

v=

3

−20

magnification=

u

−v

=

3

−1

lateral magnification is

(u−f)

2

f

2

=

(20−5)

2

25

=

9

1

Ratio of up-right portion to lateral portion is

9

1

3

1

=3:1

option B is correct

Explanation:

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