Question

A small plane with a mass of 1200 kg cruises
at 140 km h at an altitude of 1.5 km. Taking
g= 10 m s', calculate its:
(a) potential energy and
[Ans. 1.8 x 10 J]
(b) kinetic energy.
[Ans. 9.074 x 10'JI​

Answer 1

Answer:

$\mathsf{P.E. = 1.8 × {10}^{7}J}$

$\mathsf{K.E. = 9.12 × {10}^{7}J}$

Explanation:

Given

m = 1200 kg

h = 1.5km = 1500m

v = 140 km/h = 38.9 m/5 ≈ 39 m/s

(a) Potential Energy

$\mathsf{P.E. = mgh}$

$\mathsf{P.E. = (1200) (10) (1500}$

$\mathsf{P.E. = 1.8 × {10}^{7}J}$

(b) Kinetic Energy

$\mathsf{K.E. = \dfrac{1}{2}m{v}^{2}}$

$\mathsf{K.E. = \dfrac{1}{2} (1200){39}^{2}}$

$\mathsf{K.E. = 600(1521)}$

$\mathsf{K.E. = 9.12 × {10}^{7}J}$

Answer 2

Answer:

hai

Explanation:

I hope this answer helps you