Question

A small quantity, mass m,of water at a temperature theta (in °C) is poured on to a large mass M in ice which is at it's melting point if c is the specific heat capacity of water and L the latent heat of fusion of ice, then the mass of ice melted is given by

(A) ML/mctheta

(B) mctheta/ML

(C) Mctheta/L

(D) mctheta/L

Answer 1

the answer is option d

Answer 2

The mass of ice melted is given by the mc $\frac{\theta}{L}$.

Option - D

Explanation:

From the given that the certain amount of heated water is poured on eyes such that the mass of the water being bored is given we need to find out the mass of water.

We also know that the amount of heat applied to Ice by heated water would be equal to the amount of heat absorbed by ice.

Now putting this fact that we know in the form of equation we shall get                                   mc($\theta$ - 0) = M’ L,

Where 'M' mass of  water that is melting from ice and 'l' is the specific heat.  solving the equation we will get mc $\frac{\theta}{L}$.

To know more:

50g of ice at 0 degree Celsius is mixed with 40g of water at 60 degree celsius then ratio of ice and water at equilibrium is?

https://brainly.in/question/3280450