A small ring a of mass m-kg is attached at an end of a light string the other end of which is tied to a block b of mass 2m. The ring is free to move on a fixed smooth horizontal rod as shown. Find tension in the string when it becomes vertical.
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Given:
The mass of the ring is m
The mass of the block is 2m
To find:
The tension in the string.
Solution:
Using the conservation of energy.
mv²/2=mgl+mgl/3
v²=2mgl+2mgl/3
Taking LCM
v²=8gl/3
v=√8gl/3
Therefore T= 14 mg
So the tension in the string is 14 mg.
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