A small ring A of mass me g is attached at an end of a light string the other end of which is tied to a block B of mass 2m. The ring is free to move on a fixed smooth horizontal rod as shown. Find tension in the string when it becomes vertical
Answers
Answered by
0
Given:
The mass of ring A is m
The mass of ring B is 2m
To find:
The tension in the string when it becomes vertical.
Solution:
The conservation of energy will take place
mv²/2= mgl+ mgl/3
Removing common quantities
v²/2=gl+gl/3
v²/2=4gl/3
v²=8gl/3
v=√8gl/3
Therefore the Tension on the string is T=14 mg
Similar questions
English,
6 months ago
Psychology,
6 months ago
Math,
6 months ago
Math,
1 year ago
Math,
1 year ago
Computer Science,
1 year ago