Question

a small satellite is revolving near Earth's surface its orbital velocity will be nearly

Answer 1

A Small satellite is near the earth surface and it is revolving around the orbit of the earth. Therefore, At the Instant, Gravitational force will provide the centripetal force for the revolution of the satellite.

∴ mv²/R = GMm/R²

∴ v² = GM/R

∴ v = √(GM/R)

where, G is the Gravitational Constant, M is the Mass of the Earth.

This will be the Orbital velocity of the small satellite around the earth. To convert it into the easy form,

Use the Formula,

g = GM/R²

∴  GM = gR²

∴ v = √GM

v = √gR

v = 7.919 km/s.

This is the Required Orbital velocity of the satellite revolving around the Earth.

In this, it is assumed that the height at which the satellite is revolving is negligible.

Hope it helps.

Hope it helps.

Answer 2

Answer:

8km/s

Explanation: