Question

a small sphere is given charge of +20mc and second sphere of equal diameter is given a charge of _5mc two sphere are brought in contact and seperated 10 cm apart what is the force exists between them in air ​

Answer 1

After the contact between two spheres charge between them would be equally distributed.

So,

q1 = q2 =( 20 -5 )/2

= 7.5 mC

Applying couloumb's law,

F = 9* 10^9* (7.5)^2*10^-6/10^-2

F = 5.06 * 10^7 C