A small sphere of mass 200gm is attached to an inextensible string of length 130cm whose upper end is fixed to the celling. The sphere is made to describe a horizontal circle of radius 50 cm. Calculate the time period of this conical pendulum and the tension in the string.(π^2= 10)
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From the data given,
Mass = 200g.
Length = 130cm.
The time period of the pendulum, t = 2π√l/√g
Squaring on both sides,
t2 = 4π2 × 1.3/9.8
(2 pi and 9.8 is approximately the same value and so can be neglected)
Therefore, t2 = 4π2 × 1.3/9.8
t = 2.29 s.
The tension on the string is given by, mg
Therefore, 200 × 10 = 2000 gm / s2
Tension = 2N.
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