Question

A small sphere of radius r rolls without slipping inside a large hemispherical bowl

Answer 1

49) Kum 310?

sm?

Kua

2

mv

Z

T

Kt

asm?

[

[I

(b) In coming down 10 the bottom of the hemisphere loss of potential

energy = mgh = mg R. Gain in kinetic energy = (7/10) m2.

‘The normal force exerted by the small sphere at the bottom of the large

sphere will be

—mg+ 2