Question

A small stone is tied to a string of negligible mass and is rotated about the other end in vertical circle of radius 3m. the speed of the stone at the lowest point is _____ (g=10 m/s²) *
2 points
√30 m/s
10 m/s
√20 m/s
√150 m/s​

Answer 1

v=

3gr

v=

3∗9.8∗2

=7.67m/s

Answer 2

The velocity of the stone is 9.48 m/s

Step-by-step procedure

Given:

The radius of the string= 3m

The gravitational acceleration= 10 m/$s^{2}$

To find:

The speed of the stone at the lowest point:

Solution:

The velocity of the stone is given by:

v= $\sqrt{3gr}$

Putting the values,

v= $\sqrt{3 * 10 * 3}$

v= $\sqrt{90}$

v= 9.48 m/s

Result:

The speed of the stone tied to the string is 9.48 m/s

(#SPJ3)