Question

A small table weighing 40N stands on four legs, each having an area of contact of 0.001m^2. What is the pressure of the table on the floor?

Answer 1

total area of four legs = 4 × 0.001 = 0.004
so,
pressure = force / area
40/0.004 =10000 pascal or
10 kpa

Answer 2

pressure = force / area
40/0.004 =10 kpa.......