A smallbody tied to a string is revolved in a vertical circle of radius 0.8 m such that its speed at the top of the circle is 4 m/s. Find the maximum speed of the body during the motion
Answers
Answer:
6.88 m/s
Explanation: Maximum velocity is at the point where PE = 0, at the bottom.
Let the mass of the body be m.
At the highest point:
height = 2r = 2(0.8) = 1.6 ; u(velocity) = 4 m/s
Total energy = KE + PE
= mgh + 1/2 mu²
= m(9.8*1.6 + 1/2 (4)² )
= (23.68)m
At the lowest point:
Total energy = mg(0) + 1/2 mv²
(23.68)m = 0 + 1/2 m v²
23.68 = 1/2 v²
47.36 = v²
6.88 m/s = v
Since velocity at the bottom is maximum, maximum velocity is 6.88 m/s
Answer:
Maximum velocity is at the point where PE = 0, at the bottom.
Let the mass of the body be m.
At the highest point:
height = 2r = 2(0.8) = 1.6 ; u(velocity) = 4 m/s
Total energy = KE + PE
= mgh + 1/2 mu²
= m(9.8*1.6 + 1/2 (4)²)
= (23.68)m
At the lowest point:
Total energy = mg(0) + 1/2 mv²
(23.68)m = 0 + 1/2 m v²
23.68 = 1/2 v²
47.36=v²
6.88 m/s = V
Explanation: