Question

A SMOOTH BLOCK IS PLACED ON A SMOOTH WOODEN TABLETOP. A FORCE OF 14 N IS APPLIED TO KEEP 40 N MOVING AT A CONSTANT SPEED.
a) WHAT IS THE COEFFICIENT OF SLIDING FRICTION?

Answer 1

Given:       EQN:

FA= Ff = 14.0 N    Ff = µFN

W = -40.0 N

FN = 40.0 N

µ = ?

Ff = µFN

So µ = Ff/FN

µ = 14.0 N/40.0 N

µ = .350

HOPE HELPS