Question

A smooth inclined plane makes an angle of 30 to the horizontal.the constant force applied parallel to the plane to produce a 10kg block to slide up the plane with the acceleration of 1m/s is​

Answer 1

Answer:

Given acceleration of block is 1 ms  

−2

, Mass m= 10 Kg, angle of inclination= 30  

o

.

Let a constant Force is F,

From the FBD, as shown in the figure

F- mgsin(θ) =  ma

F= m(a+gsin(θ))

Putting the values,

F= 10(1+9.8×sin(30))

F=59 N

Explanation: