Question

A smooth inclined plane of angle of inclination 30 degree is placed on the floor of a compartment of a train moving with constant acceleration a When a block is placed on the inclined plane it do not slide down or up the plane The acceleration a must be
a. g b. g/2 c. g/(root 2) d. g/(root 3)

Answer 1

N=mgcosα
It is because of mgsinα the body will have an acceleration.
mgsinα=ma
m gets cancelled.
gsinα=a
here, α=30°
gsin30°=a
g*1/2=a
g/2=a    (B)

Answer 2

Answer:

g/root3 is your answer.... steps in attachment