Math, asked by fabdul3979, 1 year ago

a snail is at the bottom of a 10 foot well. everyday, he crawls up 3 feet but at night, he slips down 2 feet. how many days will it take for him to get out the well?

Answers

Answered by babelgautam16
5

it takes 10 days as

it crawls 3 foot everyday

and comes down 2 foot

does it travels 1 foot every day

therefore 10 days

Answered by syed2020ashaels
0

Answer:

The answer to the given question is the number of days the snail will take to get out of the well is 9( nine) days.

Step-by-step explanation:

Given :

A snail is at the bottom of a 10-foot well.

Every day the snail crawls 3 feet but at night it slips down 2 feet.

To find :

How many days will it take for him to get out of the well

Solution :

It is given that the snail went up 3 feet and comes down 2 feet.

On the first day, the snail went up to 3 feet and comes down 2 feet which brings him to 1 foot.

Next, it will go 4 feet and comes down to 2 feet.

Then it goes 5 feet and comes down to 3 feet

again it goes from, reaches 6 feet and crawls down to 4 feet.

From 4 it reaches 7 and moves to 5.

Then from 5 it goes to 8 and moves down to 6.

from 6 it goes to, then it comes down to 7.

from 7 it moves to 10 from 10 it comes down to 8.

from 8 after the 3 feet, it will get out of the well.

Therefore, it takes 9 days to get out of the well.

#spj3

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