Question

A snail tries to climb up tree a 22 metres . During a days the snail. climb 6 meters up and slipps2 metres down at night . How many days sha it take to reach up the tree​

Answer 1

During one day (including day and night) the snail climbs: (6 - 2) = 4 metres.

Let the number of days it would take to climb the wall up be x.

Distance traveled on last day (the moment the reaches top he will be able to cross it, thus slipping is not considered) + Distance traveled on remaining days = Wall height

6 + 4 (x − 1) = 22

4 (x − 1) = 22 − 6 = 16

x = 20/4 = 5.

Answer 2

Answer:

The snail will reach the tip of the tree during the sixth day.

Step-by-step explanation:

In a day, the snail travels 6-2 meters = 4

22/4 = 5.5

Therefore, the snail will reach the tip of the tree during the sixth day.

Hope this helps you.