Question

a snow mobile of mass 200kg is running on the snow with a velocity of 15m/s. its engine is switched off and it comes to rest by covering a distance of 60m.calculate the force of friction between the snow mobile and snow​

Answer 1

Answer:

this que answer is 245m/s

Answer 2

Answer:

-375N

Explanation:

by the third equation of motion;

v^2-u^2=2as

putting the values;

0^2-15^2=2*a*60

-225/120=a

now;F=ma

F=200*-225/120

=-375N