Question

A snowflake (1.5 x 10-9) falls to Earth’s surface under gravity (9.8 $\frac{m}{s^2}$). What is the force of the snowflake?

6.5 x 109 N
1.5 x 10-8 N
1.5 x 1010 N
0 N

Answer 1

$\begin{gathered}\pink{ \frak{Given}} \begin{cases} \sf \: initial \: velocity \: (u) = 0 \: ms ^{ - 1} \\ \\ \sf \: final \: velcity \: (v) = 20 \: ms ^{ - 1} \\ \\ \sf \: mass\: (m) = 500 \: kg \\ \\ \sf \: distance \: (s) = 25 \: m\end{cases} \\ \\\end{gathered}$

☯$\begin{gathered}\underline{\boldsymbol{According\: to \:the\: Question :}} \\\end{gathered}$

As we know that,

$\begin{gathered}\\ : \implies \displaystyle \sf \: v ^{2} - u ^{2} = 2as \\ \\ \\\end{gathered}$

$\begin{gathered}: \implies \displaystyle \sf \:(20) ^{2} - (0) ^{2} = 2 \times a \times 25 \\ \\ \\\end{gathered}$

$\begin{gathered}: \implies \displaystyle \sf \:400 - 0 = 2 \times 25a \\ \\ \\\end{gathered}$

$\begin{gathered}: \implies \displaystyle \sf \:400 = 2 \times 25a \\ \\ \\\end{gathered}$

$\begin{gathered}: \implies \displaystyle \sf \: \frac{400}{2} = 25a \\ \\ \\\end{gathered}$

$\begin{gathered}: \implies \displaystyle \sf \:a = \frac{200}{25} \\ \\ \\\end{gathered}$

$\begin{gathered}: \implies \underline{ \boxed{\displaystyle \sf \bold{\:a = 8 \: ms ^{ - 2} }} }\\ \\\end{gathered}$

____________________

$\begin{gathered}\\ \dashrightarrow \displaystyle \sf \: Force = mass \times Acceleration \\ \\ \\\end{gathered}$

$\begin{gathered}\dashrightarrow \displaystyle \sf \: Force = 500 \: kg \times 8 \: ms ^{ - 2} \\ \\ \\\end{gathered}$

$\begin{gathered}\dashrightarrow \displaystyle \sf \: Force = 4000 \: kg.ms ^{ - 2} \\ \\ \\\end{gathered}$

$\dashrightarrow \underline{ \boxed{\displaystyle \sf \: \bold{ Force = 4000 \: N}}}$