Question

A snowmobile is used to pull two sleds across the ice. The mass of the snowmobile and the rider is 320 kg. The mass of the first sled behind the snowmobile is 120 kg and the mass of the second sled is 140 kg. The ground exerts a force of 1500 N [forward] on the snowmobile. The coefficient of kinetic friction for the sleds on ice is 0.15. Assume that no other frictional forces act on the snowmobile. Calculate the acceleration of the snowmobile and the sleds.
full solution

Answer 1

Answer:

no idea i dont know sorry

Answer 2

Given:

Mass of the snowmobile and the rider= 320 kg

Mass of the first sled= 120kg

Mass of the second sled= 140kg

Forward force by ground= 1500N

The coefficient of kinetic friction= 0.15

To find:

The acceleration of the snowmobile and the sleds

Solution:

Considering the whole snowmobile and sleds in a single system, the equation for acceleration is:

Forward force - frictional force= (320+120+140) a

Frictional force= Normal reaction on the system X coefficient of kinetic friction

= (320+120+140)g X 0.15

= 870N

Substituting the value in equation,

1500 - 870 = 580 a

or a = 1.08ms⁻²

Hence, the acceleration of the snowmobile and the sleds is 1.08ms⁻²