A so-called great gambler started playing a card
game with a certain amount of money. In the first
round he tripled his amount and he gave away p to
his friend. In the second round he doubled the
amount with him and gave away 3p to his friend. In
the third round he quadrupled the amount with him
and gave away *2p to his friend and was finally left
with no money. If he gave away a total of 360 to his
friend, then what was the amount of money that he
started with (in )?
Answers
Given : gambler started playing a card game with a certain amount of money. In the first round he tripled his amount and he gave away p to
his friend. In the second round he doubled the amount with him and gave away 3p to his friend. In the third round he quadrupled the amount with him and gave away 2p to his friend and was finally left with no money. he gave away a total of 360 to his friend
To Find : what was the amount of money that he started with
Solution:
Gave to friend
p + 3p + 2p = 6p = 360
=> p = 60
in last he gave 2p = 120
and he he left with no money
he quadrupled the amount to 120 in 3rd round
so at start of 3rd round amount was 120/4 = 30
Before 3rd round he gave 3p = 180
money after 2nd round = 180 + 30 = 210
second round he doubled the amount with him
Hence amount at start of 2nd round = 210/2 = 105
Before 2nd round he gave p = 60
money after 1st round = 105 + 60 = 165
first round he tripled the amount with him
Hence amount at start of 1st round = 165/3 = 55
person started with 55
55 Gave left
165 60 105
210 180 30
120 120 0
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Step-by-step explanation:
The answer is 55
as explained below you can have a look at it
