Physics, asked by aditiagarwal1414, 11 months ago

a soap bubble , having radius of 1mm , is blown from a detergent solution having a surface tension of 2.5 × 10 ^ -2 n/m .the pressure inside the bubble equals at a point z not..below the free surface of water in a container . taking g = 10 m/s ^2 , density of water =10^3 kg/m^3 , value of z not is....​

Answers

Answered by 388rithika
5

Answer:

surface tension = 4T / R ...of a air bubble....nothing but soap bubble ...

so , = 4 T / density × g × R.....

= 4 × 2.5 × 10^-2/ 10 × 10^-3×1000

= 100× 10^-2/ 10^4×10^-3

= 1000m

= 1 cm............

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Answered by anwitabose08
2

Answer:

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Explanation:

surface tension = 4T / R of a air bubble nothing but soap bubble

so  = 4 T / density × g × R

= 4 × 2.5 × 10^-2/ 10 × 10^-3×1000

= 100× 10^-2/ 10^4×10^-3

= 1000m

= 1 cm

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