A soap bubble of 4 cm diameter containing air at 27⁰C and 760 mm pressure is expanded until the radius is 4 cm, the temperature and pressure remaining constant. How many cc of air at NTP are required for the expansion?
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0
Answer:
Initial number of moles:
n=
RT
PV
=
0.0821×300
1×
3
4π
×(0.4)
3
=0.01088
Final number of moles:
n
′
=
RT
PV
=
0.0821×300
1×
3
4π
×(0.6)
3
=0.03672
The number of moles of air added =0.03672−0.01088=2.5×10
−2
mol
Option B is correct.
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