A soap bubble of 8 cm diameter containing air at 27 degree Celsius and 760 mm hg pressure is expanded until it's radius is 8 cm , the temperature and pressure remaining constant . how many cc of air at NTP will be required for expansion ?
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Provided that the soap bubble is expanded under normal temperature and pressure conditions, the new radius is equal to 8 cm. The volume of a spherical bubble is given by the formula 4/3×π×R3. So, the expansion in volume of soap bubble is equal to, 4/3×π× (8^3- 4^3)= 1877.33 cm3
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