A soap bubble of initial radius 0.03 m is to be
blown up to double its initial radius. The surface tension of the
an film is 25 x 10-3 Nm'. Find the surface energy needed to
double the diameter of the bubble.
Answers
Answered by
1
Work done=T×△A
△A= π(0.06^2-0.03^2)
=π(0.03^2)(4-1)
=π×9×10^-4×3
=π×0.0027
work done = (25×10^-3)×(π×0.0027)
=2119.5×10^-7
=0.00021195J
hope this helps you
please mark the answer as brainliest
please FOLLOW me
Answered by
1
Answer:
Hey Buddy here's ur answer
0.00021195 Joules
Attachments:
Similar questions