a soap bubble of radius r is placed on another buble of radius 2r the radius of the surface common to both the bubble is
(a) 2r/3
(B)3r
(C)2r
(D)r
Answers
Answered by
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Hey!
Ur answer is (C).
let total pressure exerted when small bubble lies on another big bubble = T>
let r'be its radii thn,
4T/r' = 4T/r - 4T/2r
by solving r nd r' we get
r'= 2r
so, 2r is ur answer
#riShu:-)
Ur answer is (C).
let total pressure exerted when small bubble lies on another big bubble = T>
let r'be its radii thn,
4T/r' = 4T/r - 4T/2r
by solving r nd r' we get
r'= 2r
so, 2r is ur answer
#riShu:-)
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