A soccer ball is projected at an angle of 60° from the ground. It attains its maximum height in 10s. Considering acceleration due to gravity as g = 10 m/s . What is the velocity with which it was projected?
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The time for achieving the maximum height is equal to half of the time of flight. Therefore, the time of flight is 20s. The formula for time of flight is t = 2(v sinθ/g). Here, t = 20, θ = 60°, g = 10. Hence, on solving we will get the initial velocity as 115.5m/s
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