Question

a soccer is kicked and travels at a velocity of 12 m / s . after 60 s , its comes to stop . what is the ball's acceleration ?

Answer 1

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Initial Velocity = 12m/s

Final Velocity = 0m/s

Time = 60 seconds

$a = \frac{v - u}{t}$

$a = \frac{0 - 12}{60}$

$a = \frac{-12}{60}$

$a = -0.2 \: m/s$

Hence, Acceleration of the ball = -0.2m/s

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Answer 2

$\bigstar$ Given

A soccer ball is kicked and travels at a velocity of 12 m/s. After 60 seconds, it comes to a stop

$\bigstar$ To Find

Acceleration

$\bigstar$ Solution

We know that

$\red{\rm \longrightarrow a=\dfrac{v-u}{t}}$

Here

• a = acceleration
• u = initial velocity
• v = final velocity
• t = time

Units

• a = m/s²
• u = m/s
• v = m/s
• t = sec

According to the question

We are asked to find the acceleration

Therefore

We must find "a"

Given that

A soccer ball is kicked and travels at a velocity of 12 m/s. After 60 seconds, it comes to a stop

Hence

• u = 12 m/s
• v = 0 m/s [comes to rest]
• t = 60 sec

Substituting the values

We get

$\purple{\rm \longrightarrow a=\dfrac{0-12}{60} \ m/s^{2}}$

$\orange{\rm \longrightarrow a=\dfrac{-12}{60} \ m/s^{2}}$

Hence

$\pink{\rm \longrightarrow a=-0.2 \ m/s^{2}}$

Therefore

$\checkmark$ Acceleration = -0.2 m/s²