Question

. A soccer player scores 80% of the penalty kicks that he takes. Based on this, what is probability that
he will miss two in a row?

Answer 1

Answer:

I don't know this question

Answer 2

Step-by-step explanation:

Probability that the player will score = 0.8

=> Probability that the player will miss = 1 - 0.8 = 0.2

Out of 2 shots, he can miss at least one if:

#a) He misses the first and scores the second = 0.2 x 0.8 = 0.16

Or

#b) He scores the first and misses the second = 0.2 x 0.8 = 0.16

Or

#c) He misses the first and misses the second = 0.2 x 0.2 = 0.04

Thus, the required probability = 0.16 + 0.16 + 0.04 = 0.36

Alternate approach:

Probability that, out of 2 shots, he misses at least one

= 1 - Probability that, out of 2 shots, he misses none

= 1 - Probability that he scores the first and scores the second

= 1 - 0.8 x 0.8

= 1 - 0.64

= 0.36

= 36/100 = 9/25

Answer D

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