Math, asked by syedabrar, 9 months ago

a social welfare Association decide to supply drinking water for flood affected people.the drinking water id filled in a water tanker which is in the shape of a cylinder with hemisphere end ss shown in fig the whole length of the tanker is 4:2 meter n the diameter of base of the cylinder n two hemisphere are each 1:2 m.if they distrribute drinking water to 60 people in a container.each is the shape of s cylinder of raduis 21 cm n height 50 cm find the quantity of water leftbin the tankers after distribution in ltr use π=22/7​

Answers

Answered by bhagyashreechowdhury
2

The quantity of water left in the tanker after distribution in litres is 137 litres.

Step-by-step explanation:

Step 1:

The length of the water tank = 4.2 m

The diameter of the base of the cylinder and the two hemispherical ends, d = 1.2 m

So, the radius, r = d/2 = 1.2/2 = 0.6 m

 

∴ The length of the cylindrical portion of the tank, h = 4.2 - 1.2 = 3 m

Now,  

The volume of the cylindrical portion is,

= πr²h  

=  × 0.6² × 3

= 3.39 m³

and

The volume of the 2 hemispherical ends is,

= 2 × [ πr³]

=  ×  × 0.6³

= 0.905 m³

The volume of the drinking water tank is given by,

= [ volume of the cylindrical portion] + [volume of the 2 hemispherical ends]

= 3.39 m³ + 0.905 m³

= 4.295 m³

Step 2:  

The dimension of the small cylindrical containers:

Radius, r = 21 cm = 0.21 m

Height, h = 50 cm = 0.5 m

The no. of people to whom the drinking water was distributed in such small containers = 60

The volume of water distributed to 60 people is given by,

= 60 * [Volume of the small cylindrical containers]

= 60 * [πr²h]

= 60 * (22/7) * 0.21² * 0.5

= 4.158 m³

Step 3:

Therefore,

The quantity of water left in the tanker after the distribution is given by,

= [volume of the drinking water tank] – [volume of water distributed to 60 people]

= 4.295 m³ - 4.158 m³

= 0.137 m³

∵ 1 m³ = 1000 litres

= 137 litres

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