Question

a social welfare Association decided to supply drinking water for the flood affected people the drinking water is filled in a water tanker which is in the shape of a cylinder with hemispherical and as shown in the figure the whole length of the tanker is 4 point to metre and the diameter of the base cylinder and two hemisphere are each 1.2 metre if there distribute drinking water 260 people in a container each is the shape of the cylinder of radius 21 cm and height 50 cm find the quantity of water left in the tanker after distribution in litre​

Answer 1

There are some errors in the question :

the length of the tanker = 4.2m

and, drinking water is to be distributed among 60 people

Taking the above facts into consideration, the solution has been provided as follows:

Amount of water in the tanker after being distributed = (Total quantity of water) - (Distributed quantity of water)

Also, we know that,

Total quantity is equal to the capacity of the tanker

∴ Total volume of tanker = (volume of cylinder) + (volume of 2 hemispheres)

So, Volume of cylinder = $\pi$r²L cubic units = (22/7) × 0.6² × 4.2 $m^{3}$= 4.752 $m^{3}$

And, Volume of 2 hemispheres = 2 × [0.5 × (4/3)$\pi$r²]  cubic units = (4/3) × (22/7) × $0.6^{3}$ $m^{3}$ =792/875

∴ Total volume = 4.752 + 792/875 = 198/35 $m^{3}$ = 5.657

Now, Distributed quantity = 60 × (volume of a cylinder with r = 21 cm and h = 50cm) cubic units

= 60 × $\pi$r²L cubic units

= 60 × (22/7) × 21² × 50 $cm^{3}$

= 4,158,000 $cm^{3}$

= 4.158 $m^{3}$ (converting cubic cm to cubic m)

∴The volume of water left after distribution = (198/35 - 4.158) $m^{3}$

= 1.499 $m^{3}$

=  1,499 L (converting cubic metres to litres)

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Answer 2

Answer:

Quantity of water left in the tanker = 1,499 litters

Step-by-step explanation:

The quantity of water left in the tanker after distribution = Total quantity - Distributed quantity

Total quantity = Volume of the tanker

Volume of the cylinder of 4.2 m length and 1.2 m of a diameter.

Volume of cylinder = π r² L

(given L = 4.2m and diameter = 1.2m)

Substituting, we get Volume (cylinder) = 22/7 * 0.6 * 0.6 * 4.2 = 4.752 m³

Volume of 2 hemispheres at the end = 2* 2πr³/3  = 4 * 22/7 * (0.6)³ / 3 = 792 / 875 m³

Volume of tanker =  4.752 + 792/875 =  5.657 m³

Distributed quantity = 60 times the volume of a cylinder of radius 21 cm and height is 50 cm

= 60 * πr²L

= 60 * 22/6 * 21² * 50

=  4,158,000 cm³

= 4.158 m³

The quantity of water left in the tanker after distribution = 198/35 - 4.158 = 1.499 m³

1 m³= 1,000 litter

So quantity of water left in the tanker after distribution = 1.499 * 1000 = 1499 litters

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