Math, asked by boregowdajaymala, 9 months ago

A social welfare association decided to supply drinking water for the flood affected people .The drinking water is filled in a water tanker which is in the shape of a cylinder with hemispherical end as shown in the fig .The whole length of the tanker is 4.2m and the diameter of base of the cylinder and two hemispheres are each 1.2m .If they distribute drinking water to 60people in a container ,each is in the shape of a cylinder of radius 21cm and height 50cm,find the quantity of water left in the tanker after distribution in litre​

Answers

Answered by kishoreddy3
14

Answer:

Step-by-step explanation:

Attachments:
Answered by amitnrw
5

141 litre water left in Tank

Step-by-step explanation:

Length of Tanker is 4.2 m

Radius of base of cylinder = hemisphere = 1.2/2 = 0.6 m

Length of each hemisphere = 0.6 m

Length of cylindrical part = 4.2 - 0.6 - 0.6 = 3 m

Volume of Cylinder = π r²h

= π (0.6)² * 3 m³

Volume of two hemisphere = 2 * (2/3)π r³

= (4/3) π (0.6)³

= 0.8 π (0.6)²  m³

Total Volume =  3.8 π (0.6)²  m³

= 1.368 π  m³

Volume of one container = π (21/100)² * (50/100) m³

= π (.21)² / 2   m³

Volume of 60 container = 60 *  π (.21)² / 2   m³

= 30   π (.21)²    m³

= 1.323 π   m³

Water left in Tank =  1.368 π  -  1.323 π  = 0.045 π   m³

= 0.045 π   m³

= 0.141  m³

0.141  m³  

= 141 Litre

141 litre water left in Tank

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