Math, asked by rkbhat6146, 10 months ago

A social welfare Association decides ti supply drinking water for the flood affected people. The drinking water is filled in a water tanker which is in shape of a cylinder with hemisperical end. The whole length of the tank is 4.2 metre and diameter of the base cylinder and the two hemisphere are each 1.2 metre if they distribute drinking water to 60 people in a container each is in the shape of a cylinder of radius 21 cm and height 50 cm find the quantity of water left in the tanker after distribution in litre.. ​

Answers

Answered by rathnamp4370
0

Answer:

........ use CSA of frustum

Answered by aayusha5a5a5a8
0

Answer:

mark me as brainliest

Step-by-step explanation:

Expert Answer by aayush gohel

Given:

Total height of the tank (H) = 4.2 m = 420 cm

Diameter of cylinder = 1.2 m = 120 cm = Diameter of cylinder

Radius of cylinder and hemisphere (r) V o l u m e space o f space t h e space tan k space equals space V o l u m e space o f space c y l i n d e r space plus space 2 cross times V o l u m e space o f space h e m i s p h e r e equals πr squared straight h plus 2 cross times 2 over 3 πr cubed equals πr squared straight h plus 4 over 3 πr cubed equals 22 over 7 cross times 0.6 cross times 0.6 cross times 3 plus 4 over 3 cross times 22 over 7 cross times open parentheses 0.6 close parentheses cubed equals 3.3942 plus 0.9051 equals 4.2993 space straight m cubed space Radius space of space container space left parenthesis straight r subscript 1 right parenthesis space equals space 21 space cm space equals space 0.21 space straight m Height space of space container space left parenthesis straight h subscript 1 right parenthesis space equals space 50 space cm space equals space 0.5 space straight m Volume space of space 1 space container space equals space straight pi open parentheses straight r subscript 1 close parentheses squared space straight h subscript 1 space equals space 22 over 7 cross times 0.21 cross times 0.21 cross times 0.5 equals 0.0693 Volume space of space 60 space containers space equals space 60 space cross times space 0.0693 space equals space 4.158 space straight m cubed Quantity space of space water space left space in space the space tank space equals space Volume space of space tank space minus space volume space of space 60 space containers space equals space 0.1413 space straight m cubed Since space 1 space straight m cubed space equals space 1000 space litres rightwards double arrow Quantity space of space water space left space in space the space tank space equals space 141.3 space litres= Diameter/2 = 0.6 m = 60 cm

Height of the cylinder (h) = Total height - 2 x Radius of hemisphere = 4.2 - 1.2 = 3 m = 300 cm

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