Question

a social welfare association decides to supply drinking water for the flood affected people the drinking water is filled in water tanker which is in the shape of cylinder with hemispherical end is shown in figure the whole length of the timber is 4.2 metre and the diameter of base of the cylinder and two hemispherical are each 1.2 m if they distribute drinking water to 60 people in a container, each is in the shape of a cylinder of radius 21 cm and height is 50 cm find the quantity of water left in the tanker after distribution an litre π=22/7

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Answer 1

The quantity of water left in the tanker after distribution is 1,499 liter

Step-by-step explanation:

The quantity of water left in the tanker after distribution= Total quantity - Distributed quantity

Total quantity = Volume of the giving figure  = Volume of the cylinder + volume of 2 hemispheres

Volume of the cylinder of 4.2 m length and 1.2 m of a diameter.

Volume of cylinder = π r² L

= $\frac{22}{7} \times 0.6^2 \times 4.2$

= 4.752 m³

Volume of 2 hemispheres = 2×0.5 ×(4/3) π r³

= $\frac{4}{3} \times \frac{22}{7} \times 0.6$

= $\frac{792}{875}$

Total volume = 4.752 + 792/875 =  5.657 m³

Distributed quantity = 60 times the volume of a cylinder of radius 21 cm and height is 50 cm

Distributed quantity = 60 × π r² L

= $60 \times\frac{22}{7} \times 21^2 \times 50$

=  4,158,000 cm³

Since 1 m³= 1,000,000 cm³

Distributed quantity = 4,158,000 cm³ = 4.158 m³

The quantity of water left in the tanker after distribution =

 = 198/35 - 4.158 = 1.499 m³

Since 1 m³= 1,000 liter

The quantity of water left in the tanker after distribution =

=  1.499 m³ = 1.499 × 1000 = 1,499 liter

hence , The quantity of water left in the tanker after distribution is 1,499 liter

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Answer 2

Quantity of water left in the tanker = 1,499 liters

Step-by-step explanation:

The quantity of water left in the tanker after distribution = Total quantity - Distributed quantity

Total quantity = Volume of the tanker

Volume of the cylinder of 4.2 m length and 1.2 m of a diameter.

Volume of cylinder = π r² L

(given L = 4.2m and diameter = 1.2m)

Sustituting, we get Volume (cylinder) = 22/7 * 0.6 * 0.6 * 4.2 = 4.752 m³

Volume of 2 hemispheres at the end = 2* 2πr³/3  = 4 * 22/7 * (0.6)³ / 3 = 792 / 875 m³

Volume of tanker =  4.752 + 792/875 =  5.657 m³

Distributed quantity = 60 times the volume of a cylinder of radius 21 cm and height is 50 cm

= 60 * πr²L

= 60 * 22/6 * 21² * 50

=  4,158,000 cm³

= 4.158 m³

The quantity of water left in the tanker after distribution = 198/35 - 4.158 = 1.499 m³

1 m³= 1,000 liter

So quantity of water left in the tanker after distribution = 1.499 * 1000 = 1499 liters