Math, asked by sadiya273, 11 months ago

a social welfare Association decides to supply drinking water for the flood affected people the drinking water is filled in a water tanker which is in the shape of cylinder with hemispherical and as shown in the figure the whole length of the tanker is 4.2 metre and diameter of the base of the cylinder and two hemisphers are each 1.2 metre if their distribute drinking water to 60 people in a container is in the shape of cylinder of radius 21 cm and height 50 find the quantity of water left in tanker after distribution in litres​

Answers

Answered by bharatibiradar114
157

TOTAL ANSWER IS 141.4 LITRE^3

SO PLEASE MARK ME AS BRAINLIEST......

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Answered by sweetyjindal1996sj
11

Answer:

Given,

Shape of tanker is in the shape of cylinder with hemisphere

length of tanker = 4.2 m = 420 cm

diameter of the base of cylinder and hemisphere = 1.2 m = 120 cm = radius = 120/2= 60 cm

shape of container = cylinder whose radius = 21 cm and height = 50 cm

no of people to whom the water is distributed = 60

to find = water left after distribution

Explanation:

length of tanker = 420 cm ( includes cylinder and two hemisphere)

length(height ) of cylinder= 420-120= 300 cm

volume of tanker= volume of cylinder + volume of 2 hemisphere

\pi {r}^{2} h + 2 \times  \frac{2}{3} \pi {r}^{3 }  \\ \pi {r}^{2} h  +  \frac{4}{3} \pi {r}^{3 }

\pi r(rh +  \frac{4{r}^{2} }{3 })

\pi \times 60 \: (60 \times 300 +  \frac{4 \times  {(60)}^{2} }{3} ) \\60\pi(18000 + 4800) \\  = 60\pi(22800)

1368000\pi \: {cm}^{3}

volume of container =

\pi \:  {r}^{2} h \\ \pi  \times {21}^{2}  \times 50 \\ 22050\pi \:  {cm}^{3}

water for 60 people =

22050\pi \times 60 = 1323000\pi {cm}^{3}

water left in the tanker =

1368000\pi - 1323000\pi = 45000\pi {cm}^{3}

1litre \:  = 1000 {cm}^{3}

in litres the water left in the tanker =

45\pi \: litres \\ 45 \times  \frac{22}{7}  = 141.43litres

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