Math, asked by batman43032, 8 months ago

A social welfare association decides to supply drinking water for the the flood affected people the drinking water is filled in a water tanker which is in the shape of a cylinder with hemispherical end as shown in the figure the the figure. the whole length of the tanker is 4.2 meter and the diameter of base of the cylinder and two hemiapheres are each 1.2 m. if they distribute drinking water to 60 people in a container,each is in the shape of a cylinder of radius 21 cm and height 50 cm,find the quantity of water left in the tanker after distribution in liter​

Answers

Answered by monishss143
1

Answer:

THE ANSWER IS EXPLAINED IN THE PICTURE

Step-by-step explanation:

 

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Answered by psupriya789
0

Step 1:

The length of the water tank = 4.2 m

The diameter of the base of the cylinder and the two hemispherical ends,

d = 1.2 m

So, the radius, r = d/2 = 1.2/2 = 0.6 m

∴ The length of the cylindrical portion of the tank, h = 4.2 - 1.2 = 3 m

Now,

The volume of the cylindrical portion is,

= πr²h

= × 0.6² × 3

= 3.39 m³

and

The volume of the 2 hemispherical ends is,

= 2 × [ πr³]

= × × 0.6³

= 0.905 m³

∴ The volume of the drinking water tank is given by,

= [ volume of the cylindrical portion] + [volume of the 2 hemispherical ends]

= 3.39 m³ + 0.905 m³

= 4.295 m³

Step 2:

The dimension of the small cylindrical containers:

Radius, r = 21 cm = 0.21 m

Height, h = 50 cm = 0.5 m

The no. of people to whom the drinking water was distributed in cylindrical containers = 60

∴ The volume of water distributed to 60 people is given by,

= 60 * [Volume of the cylindrical containers]

= 60 * [πr²h]

= 60 * (22/7) * 0.21² * 0.5

= 4.158 m³

Step 3:

Therefore,

The quantity of water left in the tanker after the distribution is given by,

= [volume of the drinking water tank] – [volume of water distributed to 60 people]

= 4.295 m³ - 4.158 m³

= 0.137 m³

∵ 1 m³ = 1000 litres

= 137 litres

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