Math, asked by kavya1437, 11 months ago

a social welfare association decides to supply drinking water for the flood affected people. the drinking water is filled in a water tanker which is in shape of a cylinder with hemispherical end as shown in the figure the whole length of tanker is 4.2 meter and the diameter of base of the cylinder and two hemispheres are each 1.2 m. if they distribute drinking water to 60 people in a container, each is in the shape of a cylinder of radius 21 cm and height 50 cm , find the quantity of water left in the tanker after distribution in liter

Answers

Answered by monishss143
2

Answer:

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Answered by TanikaWaddle
2

quantity of water  left in the tank = 141.3 l

Step-by-step explanation:

total height of the  tank = 4.2 m = 420 cm

diameter of base of the cylinder and two hemispheres  = 1.2 m = 120 cm

volume of tank = volume of cylinder + volume of 2 hemispheres

\pi r^2 h + 2\times \frac{2}{3}\pi r ^3 \\\\\\pi r^2 h + \frac{4}{3}\pi r ^3\\\\\frac{22}{7}\times 0.6 \times 0.6 \times 3 + \frac{4}{3}\times  \frac{22}{7} \times (0.6)^3\\\\3.3942 + 0.9051 \\\\4.2993 m^3

let te radius of the conatiner 1  be r1 = 21 cm = 0.21 m

height if the container h1 = 50 cm = 0.5 m

volume of 1 container

\pi r_1^2 h_1 \\\\\frac{22}{7}\times 0.21 \times 0.21 \times 0.5 \\\\= 0.0693

volume of 60 containers = 60× 0.0693 = 4.158 m ³

quantity of water  left in the tank = volume of tank - volume of 60 containers

since  1 m ³ = 1000 liters

quantity of water  left in the tank = 141.3 l

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