Math, asked by veenaanaji1234, 10 months ago

A social welfare association decides to supply drinking water for the flood affected people. The drinking water is filled in a water tanker which is in the shape of a cylinder with hemispherical end. The whole length of the tanker is 4.2 m and the diameter of the base of the cylinder and two hemispheres are each 1.2 m. If they distribute drinking water to 60 people in a container,each is in the shape of a cylinder of radius 21cm and height 50 cm, find the quantity of water left in the tanker after distribution in litre

Answers

Answered by pushpakpati
0

Answer:

......

.

.

.

.

.

.

..

.

..

..

..

..

..

.

..

.....

Answered by psupriya789
0

Answer:

Quantity of water left in the tanker = 1,499 litters

Step-by-step explanation:

The quantity of water left in the tanker after distribution = Total quantity - Distributed quantity

Total quantity = Volume of the tanker

Volume of the cylinder of 4.2 m length and 1.2 m of a diameter.

Volume of cylinder = π r² L

(given L = 4.2m and diameter = 1.2m)

Substituting, we get Volume (cylinder) = 22/7 * 0.6 * 0.6 * 4.2 = 4.752 m³

Volume of 2 hemispheres at the end = 2* 2πr³/3  = 4 * 22/7 * (0.6)³ / 3 = 792 / 875 m³

Volume of tanker =  4.752 + 792/875 =  5.657 m³

Distributed quantity = 60 times the volume of a cylinder of radius 21 cm and height is 50 cm

= 60 * πr²L

= 60 * 22/6 * 21² * 50

=  4,158,000 cm³

= 4.158 m³

The quantity of water left in the tanker after distribution = 198/35 - 4.158 = 1.499 m³

1 m³= 1,000 litter

So quantity of water left in the tanker after distribution = 1.499 * 1000 = 1499 litters

hope it  helps u

thanks :)

MARK AS BRAINLIEST

Similar questions