Math, asked by santoshidubey332, 6 months ago

A society organised drawing compitition on 'covid-19' for all children. The following frequency distribution table gives the data of number of children and their age group age 6-7, 7-9, 9-11, 11-13, 13-15, no. of childeren 6    3     9      5      7. estimate the mean age group a) 6 b) 5 c) 4 d) 6.5. What is the upper limit of modal class a)7 b) 11 c) 13 d) 15. Comulative frequency of class interval 11-13 a) 18 b) 30 c) 9 d) 23. class mark of interval 13-15 a)6 b) 14 c) 10 d) 12. The sum of upper limit and lower limit of median class. a) 12 b) 10 c) 20 d) 28.

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Answers

Answered by supravajena8596
1

Answer:

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Answered by amitnrw
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Given : A society organised drawing compitition on 'covid-19' for all children.

data of number of children and their age

group age         6-7, 7-9, 9-11, 11-13, 13-15,

no. of children's  6    3     9      5      7.  

To Find :

What is the upper limit of modal class a)7 b) 11 c) 13 d) 15.

Cumulative frequency of class interval 11-13 a) 18 b) 30 c) 9 d) 23.

class mark of interval 13-15 a)6 b) 14 c) 10 d) 12.

The sum of upper limit and lower limit of median class. a) 12 b) 10 c) 20 d) 28.

Solution:

group age Mean   Frequency    CF         Mean * f

6-7,             6.5           6                6            39

7-9,              8              3                9            24

9-11,              10            9                18           90

11-13,            12             5                23          60

13-15            14              7               30          98

                                30                                311  

mean age group of 6-7  is 6.5

Modal Class  - 9 - 11

upper limit of modal class  = 11

Cumulative frequency of class interval 11-13  = 23

class mark of interval 13-15  = 14

median class. =9 - 11

the sum of upper limit and lower limit of median class.

9 + 11 = 20

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23 Oct 2019 ...

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