A sodium hydroxide solution containing 40% by weight of pure NaOH has a specific gravity of 1.5. What volume if this solution will be required in the preparation of 500ml of a 0.45 M NaOH solution.
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Given:
- % purity of the NaOH solution by mass is 40%
- The density of the solution (d) = 1.5g/mL
- The volume of the solution required (v) = 500 mL
- Molarity of the solution (M) = 0.45M
- Molar mass of NaOH (Mm) = 40g/mol
To find:
The volume of the impure NaOH solution required.
Solution:
- Let the volume of the impure solution required be x mL
- Mass of the impure solution required equals to (x*d) = 1.5x g
- Mass of pure NaOH is 40% of 1.5x = 0.6x g
- Mass of NaOH in the prepared solution equals ( M*v*Mm/1000) = 9 g
- Hence, 0.6x = 9 ⇒ x = 15 mL
Answer:
The volume of the impure NaOH solution required is equal to 15 mL
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