A sodium lamp of 10 W emits light
of wavelength 5896 ARMSTRONG. Assume that 66% of the
consumed energy is converted into light, then find the
number of photons emitted per Second?
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P=10W
η=66%
Energy used per sec:
10 x 0.66=6.6J
λ=5896A
E=hc/λ
E=(6.62 x 10⁻³⁴ x 3 x 10⁸)/(5896 x 10⁻¹⁰)
E=0.0033x 10⁻¹⁶J
The number of photons(n)=(Energy used per sec)/E
n=6.6/0.0033 x 10⁻¹⁶
n=2000x 10¹⁶=2000 x 10¹⁵=2 x 10¹⁸
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