Science, asked by reetdhaliwal9836, 1 year ago

A sodium salt of an unknown anion when treated with MgCl2 gives white precipitate only on boiling. The anion is

Answers

Answered by sanjeevnar6
9

Hi there,

The anion can be Sodium Bicarbonate.

# Explanation

The anion can be Sodium Bicarbonate because Sodium bicarbonate with Magnesium Chloride usually does not give white precipitates because Magnesium Bicarbonate is soluble in water. But when it boils, the bicarbonate decomposes into Carbonate. After reaction of Carbonate with the Magnesium Chloride, it gives Magnesium Carbonate white Precipitates that are insoluble in the water.

Hope it helps.

Answered by Arslankincsem
5

The anion must be Sodium Bicarbonate.

The Sodium bicarbonate after reacting with the Magnesium Chloride generally never gives the white precipitates as Magnesium Bicarbonate is water.

When it boils, the bicarbonate gets decomposed into the Carbonate.

After the reaction of Carbonate with Magnesium Chloride, it can give the white Precipitates of Magnesium Carbonate which are  not soluble in the water.

Similar questions