Question

A soft drink has a diameter of 6cm and a height of 11.5 cm. How much aluminum is used to make a can

Answer 1

Answers:

$\huge{\boxed{\sf{REQUIRED\:ALUMINIUM\:SHEET=273.48{cm}^{2}}}}$

Step by step explanation:

$\huge{\boxed{\sf{SOLUTION-}}}$

=)CAN IS IN THE SHAPE OF CYLINDER AND WE HAVE TO FIND REQUIRED ALUMINIUM SHEET FOR MAKING CAN.

>>DIAMETER OF CONTAINER=6CM

>>RADIUS OF CONTAINER=3CM

>>HEIGHT OF CONTAINER=11.5

ACCORDING TO THE QUESTION-

$t.s.a \: of \: container = 2\pi \: r(h + r) \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = 2 \times \frac{22}{7} \times 3 (11.5 + 3) \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = \frac{44}{7} \times 3 \times 14.5 \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = \frac{1914}{7} \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = 273.48 {cm}^{2}$

$\huge{\boxed{\sf{REQUIRED\:ALUMINIUM\:SHEET=273.48{cm}^{2}}}}$